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Date:      Fri, 18 May 2001 09:32:17 -0500
From:      "Jason E . Murray" <jemurray@concentric.net>
To:        Eric Boucher <eric_boucher60@yahoo.com>
Cc:        FreeBSD <freebsd-questions@FreeBSD.ORG>
Subject:   Re: Prog.: Knowing the exit code in command line
Message-ID:  <20010518093217.K407@concentric.net>
In-Reply-To: <20010518141010.32324.qmail@web9406.mail.yahoo.com>; from eric_boucher60@yahoo.com on Fri, May 18, 2001 at 07:10:10AM -0700
References:  <20010518141010.32324.qmail@web9406.mail.yahoo.com>

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Use $? to see exit codes...


Example follows:

[jemurray@plutus:~ >] ls fileexists; echo $?
fileexists
0    <-- Exit Code

[jemurray@plutus:~ >] ls filedoesnotexist; echo $?
filedoesnotexist: No such file or directory
2    <-- Exit Code



-- 
Jason E. Murray <jmurray@xo.com> - http://www.zweck.net  <><
Senior Systems and Network Administrator - XO Communications




On Fri, May 18, 2001 at 07:10:10AM -0700, Eric Boucher wrote:
> Hi there,
> 
> I wanted to know something. I remember that somebody
> told me that there were a way to know what is the exit
> code a command line return. For exemple, imagine that
> I've just type the command "ls -l" in a shell, if I
> want to know the integer that Unix just return after
> doing that command, what can I do? I think it's a
> simple command with the "$" symbol, but I didn't
> remember it.
> 
> Thank you
> 
> Eric
> 
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