Date: Mon, 3 Sep 2001 13:27:21 -0400 From: "Steve Bernard" <sbernard@gmu.edu> To: <stable@FreeBSD.ORG> Subject: RE: RAID5 Message-ID: <FJEELAGFCPJHAAMJKAKCIEIFCAAA.sbernard@gmu.edu> In-Reply-To: <030201c1349b$a0c254b0$2aa8a8c0@melim.com.br>
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Assuming identical HDs, with RAID 5 available disk space is equal to drive size*(n-1), where n is the number of drives you are using. In your case, 36GB*(3-1) == 36GB*2 == 72GB. The diskspace used for parity is not configurable. Steve -----Original Message----- From: owner-freebsd-stable@FreeBSD.ORG [mailto:owner-freebsd-stable@FreeBSD.ORG]On Behalf Of Ronan Lucio Sent: Monday, September 03, 2001 1:12 PM To: stable@FreeBSD.ORG Subject: RAID5 Hi All, I have a doubt about RAID5: If I have 3 HDs with 36 Gb each in RAID5, what is my total abaliable space? Can I select it? For example: Can I create 20 Gb for parity + 88 Gb of avaliable space? Thanks, Ronan Lucio To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-stable" in the body of the message To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-stable" in the body of the message
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