Date: Mon, 30 Jan 2017 19:09:39 +0300 From: "Andrey V. Elsukov" <bu7cher@yandex.ru> To: Warren Block <wblock@wonkity.com> Cc: Slawa Olhovchenkov <slw@zxy.spb.ru>, freebsd-hackers@freebsd.org Subject: Re: How to safely remove rest of GTP? Message-ID: <1793b0ec-3a86-5c9a-b275-aa93cd9d230e@yandex.ru> In-Reply-To: <alpine.BSF.2.20.1701300851400.85129@wonkity.com> References: <20161230124407.GN37118@zxy.spb.ru> <d79b8568-72e8-415e-4923-14e3c730267e@FreeBSD.org> <alpine.BSF.2.20.1701300851400.85129@wonkity.com>
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On 30.01.2017 18:55, Warren Block wrote: >>> GEOM: da6: the primary GPT table is corrupt or invalid. >>> GEOM: da6: using the secondary instead -- recovery strongly advised. >>> GEOM: da22: the primary GPT table is corrupt or invalid. >>> GEOM: da22: using the secondary instead -- recovery strongly advised. >>> GEOM: da6: the primary GPT table is corrupt or invalid. >>> GEOM: da6: using the secondary instead -- recovery strongly advised. >>> GEOM: da22: the primary GPT table is corrupt or invalid. >>> GEOM: da22: using the secondary instead -- recovery strongly advised. >> >> You may try attached patch, I did only basic tests, so first try >> somewhere :) > > I really like the idea of gpart being able to remove the secondary GPT, > but combining it with the existing destroy command is ambiguous. It's > hard for the user to tell what will happen, and the command itself > implies that it will destroy all partitioning. I don't see any ambiguity here. A user sees corrupted GPT, it can only destroy or recover it. It is impossible to have a corrupted GPT and some other type of partition table in the same time. So, if you use 'gpart destroy' - you want to explicitly destroy it. -- WBR, Andrey V. Elsukov
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