Date: Fri, 4 Jan 2002 12:28:03 -0600 From: Alfred Perlstein <bright@mu.org> To: Stephen Montgomery-Smith <stephen@math.missouri.edu> Cc: freebsd-hackers@freebsd.org Subject: Re: Tell gcc I have a i686 Message-ID: <20020104122803.N82406@elvis.mu.org> In-Reply-To: <3C35EE1B.484A6AD@math.missouri.edu>; from stephen@math.missouri.edu on Fri, Jan 04, 2002 at 12:02:03PM -0600 References: <3C35EE1B.484A6AD@math.missouri.edu>
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* Stephen Montgomery-Smith <stephen@math.missouri.edu> [020104 12:02] wrote:
> I want to create a Makefile for a C program that includes some Pentium
> II specific inline assembler code. How do I tell the compiler whether
> we are compiling on a i686?
>
> For Linux, I can do something like this (for gnu-make)
> Arch = $(shell arch)
> cc ...... -DArch .....
>
> and inside the program
>
> #ifdef i686
>
> But arch doesn't exist on FreeBSD.
Isn't this somewhat trivial?
ARCH=i686
CFLAGS+=-D${ARCH}
?
--
-Alfred Perlstein [alfred@freebsd.org]
'Instead of asking why a piece of software is using "1970s technology,"
start asking why software is ignoring 30 years of accumulated wisdom.'
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