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Date: Tue, 6 May 2003 11:23:52 -0500
From: "Jacques A. Vidrine" <nectar@FreeBSD.org>
To: Harti Brandt <brandt@fokus.fraunhofer.de>
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cc: freebsd-arch@FreeBSD.org
Subject: Re: `Hiding' libc symbols
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On Tue, May 06, 2003 at 05:53:16PM +0200, Harti Brandt wrote:
> JAV>Or stated more agressively, the day the FreeBSD toolchain refuses
> JAV>to allow me to define my own version of strlcpy _for use by my
> JAV>application_ is the day I find another development platform.
> 
> So if you 'hide' all the libc symbols you will to exactly that. 

Of course not.  I can define strlcpy like so

  void
  strlcpy(struct string *a, struct string *b)
  {
	  if (a->size == 0) {
		  b->size = 0;
		  return;
	  }
	  /* really copy the string */
  }

if I want to, and my application will then behave exactly as my insane
mind expects.  (this is just a sillier example of the real world
problem that was encountered)

However, since strlcpy is _not_ protected/hidden today, my application
as a whole will likely not behave as I expect.  I'll innocently call
something like getaddrinfo() and *BOOM*. :-)

Cheers,
-- 
Jacques Vidrine   . NTT/Verio SME      . FreeBSD UNIX       . Heimdal
nectar@celabo.org . jvidrine@verio.net . nectar@freebsd.org . nectar@kth.se