Date: Fri, 23 Aug 2002 01:28:26 -0500 From: Dan Nelson <dnelson@allantgroup.com> To: "Christopher J. Umina" <uminac@216-164-225-145.c3-0.wth-ubr2.sbo-wth.ma.cable.rcn.com> Cc: FreeBSD Question Mailing List <questions@FreeBSD.ORG> Subject: Re: expr replacement Message-ID: <20020823062826.GF34104@dan.emsphone.com> In-Reply-To: <20020823021838.V67143-100000@216-164-225-145.c3-0.wth-ubr2.sbo-wth.ma.cable.rcn.com> References: <20020823021838.V67143-100000@216-164-225-145.c3-0.wth-ubr2.sbo-wth.ma.cable.rcn.com>
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In the last episode (Aug 23), Christopher J. Umina said: > Hi guys & gals, > > I'm writing a simple shell script that finds percentages for me. > The problem here is that when I do the division with expr I always get a > result of 0 since it's below 1. Is there a replacement for this or am I > just doing it wrong? Take a look.. This is my command. > > percentage=`expr $dirttl / $totalsongs` To return a number from 0..100: percentage=`expr $dirttl \* 100 / $totalsongs` If you want a fractional result you'll have to use the bc command, which is an arbitrary-precision calculator. -- Dan Nelson dnelson@allantgroup.com To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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