Date: Wed, 23 Mar 2005 13:57:42 -0600 (CST) From: "Brian John" <brianjohn@fusemail.com> To: "Giorgos Keramidas" <keramida@ceid.upatras.gr>, freebsd-questions@freebsd.org Subject: Re: Simple bash script to grep files for bad keywords Message-ID: <2635.209.87.176.4.1111607862.fusewebmail-19592@webmail.fusemail.com>
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> On 2005-03-23 12:29, Brian John <brianjohn@fusemail.com> wrote:
> > Hello,
> > I am trying to write a simple bash script that will grep all files
> > in a directory (except ones that start with "00") for certain bad
> > keywords. Here is what I have so far:
>
> > #!/bin/bash
> >
> > # This is a simple script to check all sql scripts for bad keywords
> >
> > BAD_KEYWORDS='spool echo timing commit rollback'
> >
> > for i in $BAD_KEYWORDS;
> > do
> > echo "*********************************";
> > echo "GREPing for bad keyword '$i'"
> > echo "*********************************";
> > grep $i ./*;
> > done
> >
> > However, I'm not sure how to make it not grep the files that start
> > with "00". Can anyone help me with this?
>
> Use xargs, since it will buy you the extra feature of being able to
> search through arbitrarily large numbers of files:
>
> for _word in ${BAD_KEYWORDS} ;do
> find . | grep -v '^/00' |\
> xargs grep "${_word}" /dev/null
> done
>
> Tips:
>
> - The quotes in "${_word}" are probably optional, but it's better to
> be safe than sorry :-)
>
> - The /dev/null is there so that grep will get at least 2 file
> arguments, even if there is just one file in the current directory,
> effectively forcing grep(1) to print the filename of this one file
> if it happens to match the pattern.
>
Cool, I think I get it for the most part. However, what exactly am I
doing when I am piping to xargs? I can see that the filenames not
starting with '00' will be piped, but what does the '\' do? Sorry, I am
really new to scripting and *nix in general. But I am a programmer so I
learn fast.
Thanks!
/Brian
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