From owner-freebsd-questions@FreeBSD.ORG Thu Mar 17 19:06:36 2005 Return-Path: Delivered-To: freebsd-questions@freebsd.org Received: from mx1.FreeBSD.org (mx1.freebsd.org [216.136.204.125]) by hub.freebsd.org (Postfix) with ESMTP id 2516E16A4CE for ; Thu, 17 Mar 2005 19:06:36 +0000 (GMT) Received: from bayc1-pasmtp04.bayc1.hotmail.com (bayc1-pasmtp04.bayc1.hotmail.com [65.54.191.164]) by mx1.FreeBSD.org (Postfix) with ESMTP id AF33143D1D for ; Thu, 17 Mar 2005 19:06:35 +0000 (GMT) (envelope-from mweg@sympatico.ca) Message-ID: X-Originating-IP: [65.95.94.122] X-Originating-Email: [mweg@sympatico.ca] Received: from pepstep ([65.95.94.122]) by bayc1-pasmtp04.bayc1.hotmail.com over TLS secured channel with Microsoft SMTPSVC(6.0.3790.211); Thu, 17 Mar 2005 11:06:34 -0800 From: "Marco Greene (ML)" To: "FreeBSD List" Date: Thu, 17 Mar 2005 14:07:40 -0500 Message-ID: <004401c52b24$9811fd60$24c8a8c0@snowy.meadow> MIME-Version: 1.0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: quoted-printable X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6626 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2527 Importance: Normal X-OriginalArrivalTime: 17 Mar 2005 19:06:35.0101 (UTC) FILETIME=[703118D0:01C52B24] Subject: /etc/ppp/ip-up X-BeenThere: freebsd-questions@freebsd.org X-Mailman-Version: 2.1.1 Precedence: list List-Id: User questions List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Thu, 17 Mar 2005 19:06:36 -0000 Hi all, I have found a few postings regarding the /etc/ppp/ip-up and ip-down = scripts and the fact that they do not work. I am experiencing the same thing = and I have tried all of the hints that I found in those threads but with = little success. I would really like to use these scripts. Are there any = hints? -I have set the permissions to 555 -#!/bin/sh is the first line in the script Are there any other things that I may have missed? Note: pppoe is setup as per the handbook with a few modifications as = found on one of the links given by the handbook. Thanks, Marco