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Date:      Tue, 10 Sep 2002 10:58:02 -0700 (PDT)
From:      Archie Cobbs <archie@dellroad.org>
To:        Bakul Shah <bakul@bitblocks.com>
Cc:        freebsd-arch@FreeBSD.ORG
Subject:   Re: /dev/stdout behavior
Message-ID:  <200209101758.g8AHw2C33935@arch20m.dellroad.org>
In-Reply-To: <200209101717.NAA07504@wellington.cnchost.com> "from Bakul Shah at Sep 10, 2002 10:17:44 am"

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Bakul Shah writes:
> > For example, if you use fcntl() to set flags on fd 0, and then open
> > /dev/stdout, the new file descriptor you get back will have those
> > same flags set. Run the program below to see an example. This is
> > in agreement with the man page, which states that opening /dev/stdout
> > is equivalent to dup(2)'ing fd 0.
> 
> Careful reading of man stdout will reveal that opening
> /dev/stdout is equivalent to dup()ing fd 1, not fd 0.

Arg, this whole time I meant to use '1' instead of '0'...

But, hey-- now there's an even bigger bug!

-Archie

__________________________________________________________________________
Archie Cobbs     *     Packet Design     *     http://www.packetdesign.com

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