From owner-freebsd-questions Sat Sep 23 20:25: 0 2000 Delivered-To: freebsd-questions@freebsd.org Received: from mailout1-1.nyroc.rr.com (mailout1-1.nyroc.rr.com [24.92.226.146]) by hub.freebsd.org (Postfix) with ESMTP id F1C3737B422 for ; Sat, 23 Sep 2000 20:24:56 -0700 (PDT) Received: from andy (bsh1-467.twcny.rr.com [24.95.179.103]) by mailout1-1.nyroc.rr.com (8.9.3/8.9.3) with SMTP id XAA27437 for ; Sat, 23 Sep 2000 23:21:45 -0400 (EDT) Message-ID: <000701c025d6$3e635460$02c810b0@andy.compudorm.com> From: "A Minkstein" To: Subject: Jdk1.3 and expr: syntax error Date: Sat, 23 Sep 2000 23:19:24 -0400 MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_0004_01C025B4.B666B820" X-Priority: 3 X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook Express 4.72.3110.1 X-MimeOLE: Produced By Microsoft MimeOLE V4.72.3110.3 Sender: owner-freebsd-questions@FreeBSD.ORG Precedence: bulk X-Loop: FreeBSD.ORG This is a multi-part message in MIME format. ------=_NextPart_000_0004_01C025B4.B666B820 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable When I try to run the program java which is part of the jdk1.3, I get a = "expr: syntax error" message. I changed the .java_wrapper script so = that it could find it. There was a previous message which told what to = do in order to fix this problem. After trying their method, which was = to change this script file, it still gives the same error. Because of = this error, I cannot run Apache JServ with the jdk1.3 or jdk1.2.2 . If = I can't run it with those jdk's I can't execute servlets which require = Java 2 libraries. Does anyone have a solution to this problem? Bottom = line, I need to run Apache Jserv with jdk1.3. All is help is = appreciated. Thanks, Andy ------=_NextPart_000_0004_01C025B4.B666B820 Content-Type: text/html; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable

When I try to run the program java = which is part=20 of the jdk1.3, I get a "expr: syntax error" message. I = changed=20 the .java_wrapper script so that it could find it. There was a = previous=20 message which told what to do in order to fix this problem. After = trying=20 their method, which was to change this script file, it still gives the = same=20 error. Because of this error, I cannot run Apache JServ with the = jdk1.3 or=20 jdk1.2.2 . If I can't run it with those jdk's I can't execute = servlets=20 which require Java 2 libraries. Does anyone have a solution to = this=20 problem? Bottom line, I need to run Apache Jserv with = jdk1.3. All is=20 help is appreciated.

Thanks,

Andy

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