Date: 12 Oct 2001 18:21:00 -0700 From: swear@blarg.net (Gary W. Swearingen) To: Randy Bush <randy@psg.com> Cc: freebsd-questions@FreeBSD.ORG Subject: Re: date of a file Message-ID: <9k669ks5c3.69k@localhost.localdomain> In-Reply-To: <E15s8y6-0003rb-00@rip.psg.com> References: <E15s8y6-0003rb-00@rip.psg.com>
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Randy Bush <randy@psg.com> writes:
> in gnu-sh-utils, i can, for example,
>
> date -r filename +%y%m%d-%H%M%S
>
> but, in freebsd, "date -r" says give me the current date in seconds of the
> epoch.
>
> what should i be doing?
Using python or perl or awk? This gets close:
ls -lT filename | awk '{printf "%s %s %s %s\n",$9,$6,$7,$8}'
And I think the "date" command can convert dates from, say an output
of "ls" like the above (as $(ls...|awk...)) into fancy formatted
outputs (it uses strptime(3)) formats.
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