Date: Fri, 12 Oct 2001 18:24:09 -0700 From: Randy Bush <randy@psg.com> To: swear@blarg.net (Gary W. Swearingen) Cc: freebsd-questions@FreeBSD.ORG Subject: Re: date of a file Message-ID: <E15sDX7-0006zK-00@rip.psg.com> References: <E15s8y6-0003rb-00@rip.psg.com> <9k669ks5c3.69k@localhost.localdomain>
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>> in gnu-sh-utils, i can, for example,
>> date -r filename +%y%m%d-%H%M%S
>> but, in freebsd, "date -r" says give me the current date in seconds of the
>> epoch.
>> what should i be doing?
> Using python or perl or awk? This gets close:
> ls -lT filename | awk '{printf "%s %s %s %s\n",$9,$6,$7,$8}'
aha! i missed the -T option. i can hack from that. but what a grotty
kludge.
thanks.
randy
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