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Date: Fri, 27 Jun 2008 06:10:03 GMT
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To: freebsd-net@FreeBSD.org
From: Shunsuke SHINOMIYA <shino@fornext.org>
Cc: 
Subject: Re[2]: kern/125003: incorrect EtherIP header format.
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The following reply was made to PR kern/125003; it has been noted by GNATS.

From: Shunsuke SHINOMIYA <shino@fornext.org>
To: Hiroki Sato <hrs@FreeBSD.org>
Cc: freebsd-bugs@FreeBSD.org,
 bug-followup@FreeBSD.org
Subject: Re[2]: kern/125003: incorrect EtherIP header format.
Date: Fri, 27 Jun 2008 15:00:45 +0900

 > sh>  In current implementation, 0x03 is transmitted, and, next, 0x00 is
 > sh>  transmitted as version(3) and reserved(0x000) field. But I think tha=
 t
 > sh>  0x30 should be transmitted first from RFC3378.
 >=20
 >  I don't understand why you think 0x30 is correct.
 
 =46rom RFC3378
 > In summary, the EtherIP Header has two fields:
 >=20
 >       Bits 0-3:  Protocol version
 >       Bits 4-15: Reserved for future use
 >=20
 >         0   1   2   3   4   5   6   7   8   9  10  11  12  13  14  15
 >      +---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+
 >      |               |                                               |
 >      |    VERSION    |                   RESERVED                    |
 >      |               |                                               |
 >      +---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+---+
 >=20
 >                  Figure 2: EtherIP Header Format (in bits)
 >=20
 
 , first octet(bit 0,MSB to 7) consists of VERSION and a part of RESERVED.
 And VERSION is high 4 bits of the octet.
 Am I misunderstanding this?
 
 --=20
 Shunsuke SHINOMIYA <shino@fornext.org>