Date: Sat, 17 May 2003 16:55:27 +0200 (CEST) From: Niklas Saers Mailinglistaccount <niklasmls@doriath.saers.com> To: FreeBSD-Questions@freebsd.org Subject: bash shell for-loop Message-ID: <20030517164813.V37832@doriath.saers.com>
next in thread | raw e-mail | index | archive | help
Hi, I've created a small bash script that stops, and I cannot understand why it stops. It is: #!/usr/local/bin/bash for username in $(ls /home); do su -m $username /home/$username/startup.sh; done When I type this at the bash prompt, it goes well. However, when I call this script it executes the first su and then gives me: [4]+ Stopped bash /tmp/sh.sh Why does it stop? I've nowhere asked it to stop. I certainly don't want it to stop. To explain my command, I start a set of daemons for each user specified in ~/startup.sh and no user has a valid shell as I do not wish to allow them any kind of login access. Thus I have to include the "-m" What makes a bash script stop? How can I set it to ignore whatever is requesting it (errorlevels?) to stop? Cheers Nik
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?20030517164813.V37832>