Date: Tue, 17 Aug 2010 07:47:25 -0700 From: Drew Tomlinson <drew@mykitchentable.net> To: FreeBSD Questions <freebsd-questions@freebsd.org> Subject: Bash Script Help - File Names With Spaces Message-ID: <4C6AA0FD.8000100@mykitchentable.net>
next in thread | raw e-mail | index | archive | help
I have a collection of yearly top 100 Billboard mp3s in this format (all
one line - sorry if it wraps):
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 Kenny
Loggins - This Is It.mp3
I want to create symbolic links to the top 30 in 1966-1969 in another
directory for easy migration to a flash card. Thus I invoked 'find' to
get a list (again, all one line):
find -E "/archive/Multimedia/Audio/Music/Billboard Top USA Singles"
-regex '.*19[6-9][0-9]-0[0-2][0-9].*'
(OK, I know this will only return the top 29)
'find' returns the complete filename as above:
/archive/Multimedia/Audio/Music/Billboard Top USA Singles/1980-028 Kenny
Loggins - This Is It.mp3
Then I attempt to use 'basename' to extract the file name to a variable
which I can later pass to 'ln'. This seems to work:
basename "/archive/Multimedia/Audio/Music/Billboard Top USA
Singles/1980-028 Kenny Loggins - This Is It.mp3"
returns (all one line):
1980-028 Kenny Loggins - This Is It.mp3
which is what I would expect. However using it with 'find' give me this
type of unexpected result:
for i in `find -E "/archive/Multimedia/Audio/Music/Billboard Top USA
Singles" -regex '.*19[6-9][0-9]-0[1-2][0-9].*'`; do basename "${i}";done
1980-028
Kenny
Loggins
-
This
Is
It.mp3
Why is this different? And more importantly, how can I capture the file
name to $i?
Thanks,
Drew
--
Like card tricks?
Visit The Alchemist's Warehouse to
learn card magic secrets for free!
http://alchemistswarehouse.com
Want to link to this message? Use this URL: <https://mail-archive.FreeBSD.org/cgi/mid.cgi?4C6AA0FD.8000100>