Date: Fri, 12 Jul 2013 11:34:52 +1000 From: Colin House <colin@restecp.com> To: Fbsd8 <fbsd8@a1poweruser.com> Cc: questions@FreeBSD.org Subject: Re: jls usage Message-ID: <51DF5D3C.9050007@restecp.com> In-Reply-To: <51DF59B1.4020107@a1poweruser.com> References: <51DF59B1.4020107@a1poweruser.com>
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On 12/07/2013 11:19 AM, Fbsd8 wrote: > In a .sh script I'm trying to get the jid for a single jail using this code > > jid=`jls -j jailname | cut -f 1- | awk '{print $1}'` > > The first line output by jls is a title line which the cut command is > suppose to cut out so the first field on line 2 gets selected by the awk > command. This is not working as I want, I get the first field of the > title line. > > Is the cut command the correct command to us here? > > This is what the jls command shows > # /root >jls -j dir2 > JID IP Address Hostname Path > 15 10.0.10.24 dir2 /usr/jails/dir2 > > I am after the number 15 > > Thanks in advance > > _______________________________________________ > freebsd-questions@freebsd.org mailing list > http://lists.freebsd.org/mailman/listinfo/freebsd-questions > To unsubscribe, send any mail to > "freebsd-questions-unsubscribe@freebsd.org" this might do the trick for you: jls -j jailname | tail -1 | awk '{print $1}'
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