Date: Fri, 09 Nov 2001 23:39:20 -0800 From: "Christopher R. Maden" <crism@maden.org> To: freebsd-questions@freebsd.org Subject: Re: Help with AWK Message-ID: <5.1.0.14.0.20011109232932.00ae48d0@mail.maden.org> In-Reply-To: <20011110094234.B1578@ns2.wananchi.com> References: <3BEC628A.5050005@verizon.net> <20011109194842.E27386@ns2.wananchi.com> <3BEC628A.5050005@verizon.net>
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At 22:42 9-11-2001, Odhiambo Washington wrote:
>* Simon Morton <simon.morton@verizon.net> [20011110 02:17]: writing on the
>subject 'Re: Help with AWK'
>| If I understand correctly, the following should do it:
>|
>| awk -F: '$4==40{printf "^%s@.*\\.wananchi.com$:%s$:%s/:\n",$1,$3,$2;}'
>
>Hello Simon,
>
>That is not it ;). That line gives the following:
>
>#^user@.*\.wananchi.com3552YZb2gtYJeEZ1Y/:
>
>
>What I want (from master.passwd) are the following fields with the extras
>
>^$1@.*\.wananchi.com$:$3:$2:
>
>$1 = login id
>$2 = encrypted passwd
>$3 = numerical UID
>
>All with colon as the separator.
>
>I need to extract those details for two groups of users - staff (GID==20)
>and wheel (GID==0),
>all in one command, if possible.
I think Simon was on the right track, no? He just had a few extra
punctuation marks in there.
awk -F: '$4==0||$4==20{printf "^%s@.*\\.wananchi.com$:%s:%s:\n",$1,$2,$3;}'
master.passwd
I think just further tweaks to the printf ought to get what you want.
~Chris
- --
Christopher R. Maden, Principal Consultant, HMM Consulting Int'l, Inc.
DTDs/schemas - conversion - ebooks - publishing - Web - B2B - training
<URL: http://www.hmmci.com/ > <URL: http://crism.maden.org/consulting/ >
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