Date: Tue, 8 Sep 2009 14:06:54 +0200 From: Bertram Scharpf <lists@bertram-scharpf.de> To: freebsd-questions@freebsd.org Subject: Re: how to get rid of a character, 0x80? Message-ID: <20090908120654.GB18404@marge.bs.l> In-Reply-To: <4AA5F2FB.8080006@mapper.nl> References: <20090908045202.GA16556@thought.org> <4AA5F2FB.8080006@mapper.nl>
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Hi, Am Dienstag, 08. Sep 2009, 08:00:27 +0200 schrieb Mark Stapper: > Gary Kline wrote: > > anybody know why getchar() doesn't see 0x80 =3D=3D 0200? >=20 > Presumably, you want to read a capital C with cedille? (0x80 128 =C7) "\x80" is a nonbreakable space in iso8859-1/-15. (And a Euro sign in Windows-1252). Who uses cp437/cp850 on BSD? > besides.. 0x80!=3D0200 $ ruby -e 'puts 0x80, 0200' 128 128 Bertram --=20 Bertram Scharpf Stuttgart, Deutschland/Germany http://www.bertram-scharpf.de
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