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From: Tim Kientzle <kientzle@freebsd.org>
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Date: Wed, 27 Jun 2012 07:54:12 -0700
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Subject: Default processor for armv6?
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I'm filling in configuration so that an arm/armv6 build configures
GCC with a suitable default.

But I'm having some trouble figuring out what that default should be.  =
These are the ARMv6 processors supported by the in-tree GCC:

/* V6 Architecture Processors */
ARM_CORE("arm1136j-s",    arm1136js,    6J, FL_LDSCHED, 9e)
ARM_CORE("arm1136jf-s",   arm1136jfs,   6J, FL_LDSCHED | FL_VFPV2, 9e)
ARM_CORE("arm1176jz-s",   arm1176jzs,   6ZK, FL_LDSCHED, 9e)
ARM_CORE("arm1176jzf-s",  arm1176jzfs,  6ZK, FL_LDSCHED | FL_VFPV2, 9e)
ARM_CORE("mpcorenovfp",   mpcorenovfp,  6K, FL_LDSCHED, 9e)
ARM_CORE("mpcore",        mpcore,       6K, FL_LDSCHED | FL_VFPV2, 9e)

I had picked arm1136j-s originally, since that seems to be the earliest =
ARMv6 processor supported here.

My question:  Does an arm1136j-s require ARM_TP_ADDRESS?

In particular, asmacros.h uses an ARMv6K "clrex" instruction on =
processors that don't use ARM_TP_ADDRESS, which implies that =
ARM_TP_ADDRESS would be needed on the arm1136j-s.  So maybe the armv6 =
tree should default to the arm1176jz-s instead?

Can anyone give me some pointers to help unravel what processors require =
ARM_TP_ADDRESS?

Tim