Date: Wed, 27 Jun 2012 07:54:12 -0700 From: Tim Kientzle <kientzle@freebsd.org> To: arm@freebsd.org Subject: Default processor for armv6? Message-ID: <89746F7B-6B93-4112-8C32-D659E579CFAF@freebsd.org>
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I'm filling in configuration so that an arm/armv6 build configures
GCC with a suitable default.
But I'm having some trouble figuring out what that default should be. =
These are the ARMv6 processors supported by the in-tree GCC:
/* V6 Architecture Processors */
ARM_CORE("arm1136j-s", arm1136js, 6J, FL_LDSCHED, 9e)
ARM_CORE("arm1136jf-s", arm1136jfs, 6J, FL_LDSCHED | FL_VFPV2, 9e)
ARM_CORE("arm1176jz-s", arm1176jzs, 6ZK, FL_LDSCHED, 9e)
ARM_CORE("arm1176jzf-s", arm1176jzfs, 6ZK, FL_LDSCHED | FL_VFPV2, 9e)
ARM_CORE("mpcorenovfp", mpcorenovfp, 6K, FL_LDSCHED, 9e)
ARM_CORE("mpcore", mpcore, 6K, FL_LDSCHED | FL_VFPV2, 9e)
I had picked arm1136j-s originally, since that seems to be the earliest =
ARMv6 processor supported here.
My question: Does an arm1136j-s require ARM_TP_ADDRESS?
In particular, asmacros.h uses an ARMv6K "clrex" instruction on =
processors that don't use ARM_TP_ADDRESS, which implies that =
ARM_TP_ADDRESS would be needed on the arm1136j-s. So maybe the armv6 =
tree should default to the arm1176jz-s instead?
Can anyone give me some pointers to help unravel what processors require =
ARM_TP_ADDRESS?
Tim
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