From owner-freebsd-questions  Sun Dec  2 14:49:57 2001
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Date: Sun, 2 Dec 2001 14:49:47 -0800
From: "Crist J . Clark" <cristjc@earthlink.net>
To: Darren Pilgrim <dmp@pantherdragon.org>
Cc: "Gary W. Swearingen" <swear@blarg.net>,
	freebsd-questions@FreeBSD.ORG
Subject: Re: Changing $IFS in a bash shell
Message-ID: <20011202144947.B27117@blossom.cjclark.org>
Reply-To: cjclark@alum.mit.edu
References: <3C097584.B51ECEBC@pantherdragon.org> <20011201173255.N13613@blossom.cjclark.org> <ausnaup7da.nau@localhost.localdomain> <3C0AABE1.1DB4F9EC@pantherdragon.org>
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In-Reply-To: <3C0AABE1.1DB4F9EC@pantherdragon.org>; from dmp@pantherdragon.org on Sun, Dec 02, 2001 at 02:32:01PM -0800
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On Sun, Dec 02, 2001 at 02:32:01PM -0800, Darren Pilgrim wrote:
> I solved this one on the command line:
> 
> $ IFS="
> > "
> 
> This gives the result I want insofar as how item list word-splitting
> works now:
> 
> $ ls
> file 1  file 2  file 3  file 4
> $ for dir in `find * -type f` ; do echo -n "test "; echo ${dir}; done
> test file 1
> test file 2
> test file 3
> test file 4
> 
> Now, how do I do the above in a script?  Like this?

Actually, after all of this trying to get a newline in IFS, I think,

  $ IFS=""

Will work fine for what you want too. Either way, there is no reason
not to put,

  IFS="
  "

Or

  IFS=""

Into a script.
-- 
Crist J. Clark                     |     cjclark@alum.mit.edu
                                   |     cjclark@jhu.edu
http://people.freebsd.org/~cjc/    |     cjc@freebsd.org

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