Date: Sat, 10 Nov 2001 17:32:54 +0200 From: Giorgos Keramidas <charon@labs.gr> To: Odhiambo Washington <wash@wananchi.com> Cc: questions@freebsd.org Subject: Re: Help with AWK Message-ID: <20011110153254.GA12138@hades.hell.gr> In-Reply-To: <20011110094234.B1578@ns2.wananchi.com> References: <20011109194842.E27386@ns2.wananchi.com> <3BEC628A.5050005@verizon.net> <20011110094234.B1578@ns2.wananchi.com>
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Odhiambo Washington <wash@wananchi.com> wrote
> * Simon Morton <simon.morton@verizon.net> [20011110 02:17]:
> | If I understand correctly, the following should do it
> |
> | awk -F: '$4==40{printf "^%s@.*\\.wananchi.com$:%s$:%s/:\n",$1,$3,$2;}'
>
> Hello Simon,
>
> That is not it ;). That line gives the following
>
> #^user@.*\.wananchi.com3552YZb2gtYJeEZ1Y/
>
> What I want (from master.passwd) are the following fields with the extra
>
> ^$1@.*\.wananchi.com$:$3:$2
>
> $1 = login id
> $2 = encrypted passwd
> $3 = numerical UID
>
> All with colon as the separator.
>
> I need to extract those details for two groups of users - staff (GID==20) and wheel (GID==0),
> all in one command, if possible.
a) Use egrep to limit the lines of master.passwd that interest you.
(Not that it makes a great difference, but this way you separate
the problem in two smaller problems: selecting lines, and printing
those we selected with a format).
egrep -e '^[^:]*:[^:]*:[^:]*:(20|0):.*$' master.passwd
b) Then print only those fields you're interested in with awk's printf().
awk '{printf "^%s@.*\\.wananchi.com$:%s:%s\n",$1,$3,$2}'
Testing this on my machine prints:
# egrep -e '^[^:]*:[^:]*:[^:]*:(20|0):.*$' master.passwd | \
awk -F: '{printf "^%s@.*\\.wananchi.com$:%s:%s\n",$1,$3,$2}'
^root@.*\.wananchi.com$:0:PASSWORD
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