Date: Tue, 23 Oct 2012 18:13:05 -0700 From: Gary Kline <kline@thought.org> To: Gezeala =?iso-8859-1?B?TS4gQmFjdfFv?= II <gezeala@gmail.com> Cc: Olivier Nicole <olivier.nicole@cs.ait.ac.th>, Polytropon <freebsd@edvax.de>, FreeBSD Mailing List <freebsd-questions@freebsd.org> Subject: Re: way way off topic Message-ID: <20121024011305.GH29440@ethic.thought.org> In-Reply-To: <CAJKO3mVU9oZPrhYcxPUm-npE98DAwObcKjwCKt_t9yK8u%2B0h-g@mail.gmail.com> References: <20121023042007.GA14738@ethic.thought.org> <CA%2Bg%2BBvgaYY-nh9d89a7ytf9RAgMSjFNHPh3GzNqNG0xPFEX9BQ@mail.gmail.com> <20121023085249.5c742ccc.freebsd@edvax.de> <20121024000714.GG29440@ethic.thought.org> <CAJKO3mVU9oZPrhYcxPUm-npE98DAwObcKjwCKt_t9yK8u%2B0h-g@mail.gmail.com>
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On Tue, Oct 23, 2012 at 05:52:02PM -0700, Gezeala M. Bacuņo II wrote: > % change = ( (present - past) / past ) * 100 > yeah, this is exactly it for my "how much more is 16 than 15" problem. or the ages example. It's 6.6[bar-over .6]% this is probably close to or exactly what was the core of my C [argc, *srgv[]] program. my error was in not understanding the logic that polttropon has given below. if/when I ever find that v short exercise, THIS time, il'l remember to 'splain stuff in /* * comments */ > > On Tue, Oct 23, 2012 at 5:07 PM, Gary Kline <kline@thought.org> wrote: > > On Tue, Oct 23, 2012 at 08:52:49AM +0200, Polytropon wrote: > >> On Tue, 23 Oct 2012 11:31:18 +0700, Olivier Nicole wrote: > >> > Gary, > >> > > >> > On Tue, Oct 23, 2012 at 11:20 AM, Gary Kline <kline@thought.org> wrote: > >> > > > >> > > apologies up front for this math type quandary. I had it in a std C program, > >> > > but 3+ hours of grepping havent found it. I would have bet my last cent that I > >> > > had a summary Somewhere, but cant find that either. > >> > > > >> > > here is the problem as best I can remember it. > >> > > > >> > > > >> > > let's say that john is 8 and his older friend, jim, is 22. > >> > > how much older is exact percentage terms is jim? > >> > > >> > That should be 22/8=2.75 > >> > Jim is 275% older than John > >> > >> Jim is 175% _older_. Why? Because 100% older means 16 years, > >> as 100% refers to 8 years (8+8=16, 200% older is 8+8+8=24). > >> Percentage is always a reference to something else, in this > >> question, Jim's age in relation to John's. The word "older" > >> means "adding percentage", refering to the base value of 8, > >> "divided in 100 parts" (floating point considerations aside), > >> to finally reach the value 22. > >> > >> If the question would be different, say, "What's the percentage > >> of John's age regarding Jim's age?" In that case, it would be > >> 8/22=0.3636 being 36%. Obvious: John's age is approximately > >> 1/3 of Jim's age. > >> > >> The easiest way for creating the proper calculation is to refer > >> to the equation > >> > >> percentage * 100 > >> percentage value = ---------------- > >> base value > >> > >> and resolve it to whatever is required. > >> > >> -- > >> Polytropon > >> Magdeburg, Germany > >> Happy FreeBSD user since 4.0 > >> Andra moi ennepe, Mousa, ... > > > > > > yo; I THInk this is it. around line 4542 in my ~/.HowTo file:: > > > > > > > > %%% find percent inc/dec [increase/decrease] between two numbers. > > > > Always figure the percentage of change relative to the original value! > > For instance: * Suppose a certain item used to sell for seventy-five > > cents a pound, you see that it's been marked up to eighty-one cents a > > pound. What is the percent increase? > > > > First, I have to find the absolute > > increase: > > Reserved 81 - 75 = 6 > > > > The price has gone up six cents. Now I can find the > > percentage increase over the original price. > > > > This percentage increase is the relative change: 6/75 = 0.08 > > ...or an 8% increase in price per pound. > > > > > > > > So I was wrong about ages or speed; it's the % betwen two ints; > > here, the inc/dec [or change] between 75 cents as compared to > > an inflated increase of 81 cents. > > > > 1. find abs increase: 81-75 = 6; > > 2 find the % increase over the *original* value. 6.0/75.0 > > 3. percent increase using doubles is 0.08; so a markup of six > > cents is an 8% rate. > > > > > > so: going back to the ages example with john bein 8, jim, 22. > > 22-8 is 14. > > 14.0/8.0 = 1.750000 > > > > 175%. jim is 175% times older than john. which is what you found, > > polyt. {I'll have to re-read your logic now that im awake..} > > > > Or, how much more, in % is 16t than 15, it is 1.0/15.0 which is 6%. > > etc, etc. > > > > Hm. that's 0 for gary, 729 for polytrop!! > > > > Ah, life:: accept no substitutes. > > > > > > > > > > -- > > Gary Kline kline@thought.org http://www.thought.org Public Service Unix > > Twenty-six years of service to the Unix community. > > > > _______________________________________________ > > freebsd-questions@freebsd.org mailing list > > http://lists.freebsd.org/mailman/listinfo/freebsd-questions > > To unsubscribe, send any mail to "freebsd-questions-unsubscribe@freebsd.org" -- Gary Kline kline@thought.org http://www.thought.org Public Service Unix Twenty-six years of service to the Unix community.
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