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Date:      Sun, 12 Aug 2012 23:10:28 -0000
From:      Stephen Montgomery-Smith <stephen@missouri.edu>
To:        Bruce Evans <brde@optusnet.com.au>
Cc:        Diane Bruce <db@db.net>, John Baldwin <jhb@freebsd.org>, David Chisnall <theraven@freebsd.org>, Bruce Evans <bde@freebsd.org>, Steve Kargl <sgk@troutmask.apl.washington.edu>, David Schultz <das@freebsd.org>, Peter Jeremy <peter@rulingia.com>, Warner Losh <imp@bsdimp.com>
Subject:   Re: Use of C99 extra long double math functions after r236148
Message-ID:  <500A1638.5090601@missouri.edu>
Resent-Message-ID: <20120812231021.GW20453@server.rulingia.com>
In-Reply-To: <20120721122309.R856@besplex.bde.org>
References:  <20120714120432.GA70706@server.rulingia.com> <20120717084457.U3890@besplex.bde.org> <5004A5C7.1040405@missouri.edu> <5004DEA9.1050001@missouri.edu> <20120717200931.U6624@besplex.bde.org> <5006D13D.2080702@missouri.edu> <20120718205625.GA409@troutmask.apl.washington.edu> <500725F2.7060603@missouri.edu> <20120719025345.GA1376@troutmask.apl.washington.edu> <50077987.1080307@missouri.edu> <20120719032706.GA1558@troutmask.apl.washington.edu> <5007826D.7060806@missouri.edu> <5007AD41.9070000@missouri.edu> <20120719205347.T2601@besplex.bde.org> <50084322.7020401@missouri.edu> <20120720035001.W4053@besplex.bde.org> <50085441.4090305@missouri.edu> <20120720162953.N2162@besplex.bde.org> <20120720184114.B2790@besplex.bde.org> <50095CDE.4050507@missouri.edu> <20120721011112.D5008@besplex.bde.org> <5009BB46.3050001@missouri.edu> <20120721122309.R856@besplex.bde.org>

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On 07/20/2012 09:33 PM, Bruce Evans wrote:
> On Fri, 20 Jul 2012, Stephen Montgomery-Smith wrote:
>
>> On 07/20/2012 11:25 AM, Bruce Evans wrote:
>>> On Fri, 20 Jul 2012, Stephen Montgomery-Smith wrote:
>>
>>
>>> %             x0 = (float)x;
>>> %             x1 = x - x0;
>>> %             y0 = (float)y;
>>> %             y1 = y - y0;
>>>
>>> A good way to do the hi+lo decompositions.
>>
>> That was the way I tried first.  But it didn't work for me!
>>
>> But I see you changed things further down, so that is probably why it
>> works for you.
>
> I didn't understand what was happening before, but think I can explain it
> now:
> - the above gives correct hi+lo decompositions.  Both hi and lo are usually
>    nonzero.  The code below did't really understand hi+lo decompositions,
>    and often increases the final error (relative to naive code).
> - your code often gives null but backwards hi+lo decompositions, with hi
> = 0
>    and lo = full value.  The code below did't really understand hi+lo
>    decompositions.  But when hi = 0, it is especially easy to add and
>    multiply it exactly, so the final error isn't increased so often.

Yes.  That was my intention.  But I will go with whatever works best - I 
am not sold on one solution over another.





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