Date: Wed, 27 Jun 2012 10:25:46 -0400 From: Aleksandr Miroslav <alexmiroslav@gmail.com> To: freebsd-questions@freebsd.org Subject: shell scripting: grepping multiple patterns, logically ANDed Message-ID: <CACcSE1zwRcU_VQ16A2wiG4yWk4RBRykTXBono3xspw97zhDs7w@mail.gmail.com>
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hello, I'm not sure if this is the right forum for this question, but here goes. I have the following in a shell script: #!/bin/sh if [ "$#" -eq "0" ]; then find /foo fi if [ "$#" -eq "1" ]; then find /foo | grep -i $1 fi if [ "$#" -eq "2" ]; then find /foo | grep -i $1 | grep -i $2 fi if [ "$#" -eq "3" ]; then find /foo | grep -i $1 | grep -i $2 | grep -i $3 fi Is there an easier/shorter way to do this? If there are 15 arguments supplied on the command line, I don't necessarily want to build 15 if statements. Thanks in advance for your answers.
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