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Date:      Sun, 06 Jul 2014 01:36:19 +0000
From:      bugzilla-noreply@freebsd.org
To:        freebsd-jail@FreeBSD.org
Subject:   [Bug 191279] [jail] jail allow.sysvipc - doesn't work until jail is started TWICE after reboot
Message-ID:  <bug-191279-9824-suCGgEzLct@https.bugs.freebsd.org/bugzilla/>
In-Reply-To: <bug-191279-9824@https.bugs.freebsd.org/bugzilla/>
References:  <bug-191279-9824@https.bugs.freebsd.org/bugzilla/>

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https://bugs.freebsd.org/bugzilla/show_bug.cgi?id=191279

joeb1@a1poweruser.com changed:

           What    |Removed                     |Added
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                 CC|                            |joeb1@a1poweruser.com

--- Comment #5 from joeb1@a1poweruser.com ---
When you say the allow.sysvipc parameter has no effect on a jails first start
after system boot. Just how are you determining this? 
Do you see the "allow.sysvipc" listed by the "jls -name -j jailname" command.

I installed 10.0 from disc1.iso to a empty hard drive and running qjail-3.4 and
after starting the jail "jls -name -j jailname" shows "allow.sysvipc" which
means its enabled, and no error messages in the jails console log. 

Seeing jls showing the "allow.sysvipc" instead of "allow.nosysvipc" is the only
indicator I have available to verify its being set correctly. This indicator
does not really prove the sysvipc function for the jail is functional. As far
as I know you need to run some application in the jail that requires sysvipc
access as the only true test. This application may have to be started one time
to set some application internal default setting before it knows sysvipc is
enabled on its second start. Look for a application configure file to set
sysvipc as the default instead of the tcp default setting. What application are
you running in the jail and how does that application get started?

Almost 99% sure your problem is caused by your jailed application and not qjail
or jail(8).

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