Date: Mon, 03 Nov 2003 10:51:59 +0100 From: Alexander Marx <mad-ml@madness.at> To: Odhiambo Washington <wash@wananchi.com> Cc: freebsd-questions@freebsd.org Subject: Re: How does FreeBSD calculate disk sizes Message-ID: <3FA6253F.4050101@madness.at> In-Reply-To: <20031103090715.GC20234@ns2.wananchi.com> References: <20031103090715.GC20234@ns2.wananchi.com>
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Odhiambo Washington wrote: > Hello users, > > I have a disk which is actually 72GB. 2GB has been used as swap while > the rest was given to /. > > Can someone explain to me what I could be missing here, because what > I am seeing isn't what I expect. Perhaps it's just right while I am > the dumb one. Why isn't the whole size reported? [...] first of all, a "72GB harddisk" isn't actually a 72GB harddisk; this might sound funny, but harddisk manufacturers are engineering people and they are usually thinking in terms of 1000s (see http://www.seagate.com/support/kb/disc/bytes.html) so your disk actually only holds 72000000000 bytes (~69GB) ... which is perfectly consistent with your fdisk output. further, reading tunefs(8) you will find, that per default your filesystem reserves some space (8%) for root ... : -m minfree : Specify the percentage of space held back from normal users; the : minimum free space threshold. The default value used is 8%. .. subtracting 8% from the remaining 69GB roughly gives 64GB. so your disk is just fine. regards, alex.
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