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Date:      Sat, 7 Feb 2004 14:17:35 +0100
From:      Stijn Hoop <stijn@win.tue.nl>
To:        Garrett Wollman <wollman@khavrinen.lcs.mit.edu>
Cc:        Claus Guttesen <cguttesen@yahoo.dk>
Subject:   Re: Reserved space (WAS: How to calculate bsdlabel size)
Message-ID:  <20040207131735.GA2803@pcwin002.win.tue.nl>
In-Reply-To: <200402061857.i16IvBOc050219@khavrinen.lcs.mit.edu>
References:  <20040206072244.GT908@cirb503493.alcatel.com.au> <20040206084458.53207.qmail@web14101.mail.yahoo.com> <200402061857.i16IvBOc050219@khavrinen.lcs.mit.edu>

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On Fri, Feb 06, 2004 at 01:57:11PM -0500, Garrett Wollman wrote:
> <<On Fri, 6 Feb 2004 09:44:58 +0100 (CET), =3D?iso-8859-1?q?Claus=3D20Gut=
tesen?=3D <cguttesen@yahoo.dk> said:
>=20
> > Does the algorithm(s) rely only on percentage of free
> > space? On a five TB (netto) filesystem eigth percent
> > is approx. 410 GB which seems quite alot.
>=20
> A good Data Structures text will prove to you that the efficiency of
> hashing algorithms of the sort that the UFS block allocator uses
> depends only on the occupancy ratio and not on the absolute number of
> free hash slots.

Which translates into what wrt this question? That the 8% of free space
is really necessary for the UFS block allocator to function efficiently?

Just curious,

--Stijn

--=20
The very powerful and the very stupid have one thing in common.  Instead of
altering their views to fit the facts, they alter the facts to fit their vi=
ews
=2E.. which can be very uncomfortable if you happen to be one of the facts =
that
needs altering.
		-- Doctor Who, "Face of Evil"

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