Date: Sat, 10 Aug 2013 02:52:55 +0200 From: Damien Fleuriot <ml@my.gd> To: Peter Wemm <peter@wemm.org> Cc: Kimmo Paasiala <kpaasial@gmail.com>, s m <sam.gh1986@gmail.com>, FreeBSD Net <freebsd-net@freebsd.org> Subject: Re: how calculate the number of ip addresses in a range? Message-ID: <CE96AB08-2FB1-4892-A60B-AFF98121FF0B@my.gd> In-Reply-To: <CAGE5yCrZx%2Bey57XMcOjFt6iWrrRGJtbA1PH-1fHC1aU7MT_qXg@mail.gmail.com> References: <CAA_1SgEEeyCOk%2Bi9Zp725RfQ9s0tpELXL0SSBeiN%2B60z%2BxqYUg@mail.gmail.com> <CAGE5yCoBYS2%2BsHoQXZvWMNPTQeEEtDX7LAKSBHJAZ4_rA2-byQ@mail.gmail.com> <8B53C542-5CC3-45E6-AA62-B9F52A735EE5@my.gd> <CAGE5yCqURzYF2TYez6S6y=x4rWtKdL%2B-3zjGsDuz2LqGb18-RQ@mail.gmail.com> <CA%2B7WWSf_i7b66xSFP3Gk20Cq7v0mX_ynQg61GM9u1_0vZF5-wQ@mail.gmail.com> <CAGE5yCrZx%2Bey57XMcOjFt6iWrrRGJtbA1PH-1fHC1aU7MT_qXg@mail.gmail.com>
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On 10 Aug 2013, at 01:17, Peter Wemm <peter@wemm.org> wrote: > On Fri, Aug 9, 2013 at 4:07 PM, Kimmo Paasiala <kpaasial@gmail.com> wrote:= >> On Sat, Aug 10, 2013 at 1:44 AM, Peter Wemm <peter@wemm.org> wrote: >>> On Fri, Aug 9, 2013 at 9:34 AM, Fleuriot Damien <ml@my.gd> wrote: >>>>=20 >>>> On Aug 8, 2013, at 10:27 AM, Peter Wemm <peter@wemm.org> wrote: >>>>=20 >>>>> On Thu, Aug 8, 2013 at 12:04 AM, s m <sam.gh1986@gmail.com> wrote: >>>>>> hello guys, >>>>>>=20 >>>>>> i have a question about ip addresses. i know my question is not relat= ed to >>>>>> freebsd but i googled a lot and found nothing useful and don't know w= here i >>>>>> should ask my question. >>>>>>=20 >>>>>> i want to know how can i calculate the number of ip addresses in a ra= nge? >>>>>> for example if i have 192.0.0.1 192.100.255.254 with mask 8, how many= ip >>>>>> addresses are available in this range? is there any formula to calcul= ate >>>>>> the number of ip addresses for any range? >>>>>>=20 >>>>>> i'm confusing about it. please help me to clear my mind. >>>>>> thanks in advance, >>>>>=20 >>>>> My immediate reaction is.. is this a homework / classwork / assignment= ? >>>>>=20 >>>>> Anyway, you can think of it by converting your start and end addresses= >>>>> to an integer. Over simplified: >>>>>=20 >>>>> $ cat homework.c >>>>> main() >>>>> { >>>>> int start =3D (192 << 24) | (0 << 16) | (0 << 8) | 1; >>>>> int end =3D (192 << 24) | (100 << 16) | (255 << 8) | 254; >>>>> printf("start %d end %d range %d\n", start, end, (end - start) + 1); >>>>> } >>>>> $ ./homework >>>>> start -1073741823 end -1067122690 range 6619134 >>>>>=20 >>>>> The +1 is correcting for base zero. 192.0.0.1 - 192.0.0.2 is two >>>>> usable addresses. >>>>>=20 >>>>> I'm not sure what you want to do with the mask of 8. >>>>>=20 >>>>> You can also do it with ntohl(inet_addr("address")) as well and a >>>>> multitude of other ways. >>>>=20 >>>>=20 >>>> Hold on a second, why would you correct the base zero ? >>>> It can be a valid IP address. >>>=20 >>> There is one usable address in a range of 10.0.0.1 - 10.0.0.1. >>> Converting to an integer and subtracting would be zero. Hence +1. >>>=20 >>> -- >>=20 >> To elaborate on this, for every subnet regardless of the address/mask >> combination there are two unusable addresses: The first address aka >> the "network address" and the last address aka the "broadcast >> address". There may be usable address in between the two that end in >> one of more zeros but those addresses are still valid. Some operating >> systems got this horribly wrong and marked any address ending with a >> single zero as invalid, windows 2000 was one of them. >>=20 >> -Kimmo >=20 > If we go back to the orignal question: "if i have 192.0.0.1 > 192.100.255.254 how many ip addresses are available in this range?" > They're all in the same 192.0.0.0/8. Broadcast or sink addresses > don't factor into it. >=20 > --=20 > Peter Wemm - peter@wemm.org; peter@FreeBSD.org; peter@yahoo-inc.com; KI6FJ= V > UTF-8: for when a ' just won\342\200\231t do. > <brueffer> ZFS must be the bacon of file systems. "everything's better wit= h ZFS" Peter, The original question is "how to calculate a range", nobody said it should b= e a /24, that was merely an example.=
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