Date: Wed, 9 Sep 2009 17:21:46 +0100 From: "Daniel Bye" <danielby@slightlystrange.org> To: freebsd-questions@freebsd.org Subject: Re: Regex Help - Greedy vs. Non-Greedy Message-ID: <20090909162146.GB96342@torus.slightlystrange.org> In-Reply-To: <4AA7D49D.8090002@mykitchentable.net> References: <4AA7D49D.8090002@mykitchentable.net>
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--f2QGlHpHGjS2mn6Y Content-Type: text/plain; charset=us-ascii Content-Disposition: inline Content-Transfer-Encoding: quoted-printable On Wed, Sep 09, 2009 at 09:15:25AM -0700, Drew Tomlinson wrote: > I'm trying to do a search and replace in vim. I have lines like this: > http://site1/dir/; > http://site2/dir/;LastName, FirstName;Phone; > http://site3/dir/;LastName, FirstName; > http://site4/dir/; >=20 > I'm want to match "http:*" and stop matching at the first ";". My basic= =20 > regex is: >=20 > /http:.\+;/ >=20 > But it's matching *all* the semi-colons. Thus I've Googled and tried=20 > various incatations to try and make my regex "non-greedy" but I can't=20 > seem to come up with the correct combination. >=20 > How can I write a regex that stops matching at the first semi-colon? Tested in vi, not vim: /http:[^;]*/ Dan --=20 Daniel Bye _ ASCII ribbon campaign ( ) - against HTML, vCards and X - proprietary attachments in e-mail / \ --f2QGlHpHGjS2mn6Y Content-Type: application/pgp-signature Content-Disposition: inline -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.13 (FreeBSD) iEYEARECAAYFAkqn1hoACgkQixf5fBYiFmp4CwCfdwHoN+8z6TMnlGNdgSssx8D3 0q4AoL6jtpcdjsgOYJqzE6JIeHkkSxEe =mD/3 -----END PGP SIGNATURE----- --f2QGlHpHGjS2mn6Y--
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