From owner-freebsd-questions@FreeBSD.ORG Mon Jun 30 11:52:02 2003 Return-Path: Delivered-To: freebsd-questions@freebsd.org Received: from mx1.FreeBSD.org (mx1.freebsd.org [216.136.204.125]) by hub.freebsd.org (Postfix) with ESMTP id C4E5B37B401 for ; Mon, 30 Jun 2003 11:52:02 -0700 (PDT) Received: from col-msxproto1.col.missouri.edu (col-msxproto1.col.missouri.edu [128.206.3.151]) by mx1.FreeBSD.org (Postfix) with ESMTP id 0484B44001 for ; Mon, 30 Jun 2003 11:52:02 -0700 (PDT) (envelope-from dooleyr@missouri.edu) Received: from COL-EMAIL1.col.missouri.edu ([128.206.3.131]) by col-msxproto1.col.missouri.edu with Microsoft SMTPSVC(5.0.2195.6673); Mon, 30 Jun 2003 13:52:01 -0500 From: Ryan Dooley To: Chris Dillon In-Reply-To: <20030630123419.Y15622@duey.wolves.k12.mo.us> References: <1056655254.29167.5.camel@appleseed.iats.missouri.edu> <20030630123419.Y15622@duey.wolves.k12.mo.us> Content-Type: text/plain Content-Transfer-Encoding: 7bit Message-Id: <1056999120.17014.26.camel@appleseed.iats.missouri.edu> Mime-Version: 1.0 X-Mailer: Ximian Evolution 1.4.0 Date: 30 Jun 2003 13:52:00 -0500 X-OriginalArrivalTime: 30 Jun 2003 18:52:01.0420 (UTC) FILETIME=[B0D874C0:01C33F38] cc: questions@freebsd.org Subject: Re: tree-based quotas for UFS/UFS2? X-BeenThere: freebsd-questions@freebsd.org X-Mailman-Version: 2.1.1 Precedence: list List-Id: User questions List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Mon, 30 Jun 2003 18:52:03 -0000 > By tree-based you mean the ability to define "this directory and > everything under it gets X amount of storage, regardless of owner"? > If so, I also wish this ability existed, and I've talked with several > administrators of ISPs that sorely need that ability as well. If it > is a monumental undertaking, maybe some hosting providers who use > FreeBSD and would greatly benefit from such a feature would be willing > to fund it. Yup... quotas per directory (not per user or group). I've been thinking I might take on such a project (I just need to devote some time on the good old calendar ;-) I wouldn't think this would be that difficult (it's not trivial but I wouldn't think it is an evil monster :-) Ryan