Date: Wed, 16 Jun 2010 08:14:38 +0800 From: Aiza <aiza21@comclark.com> To: "questions@freebsd.org" <questions@freebsd.org> Subject: Re: * wildcard in.sh script Message-ID: <4C18176E.7030008@comclark.com> In-Reply-To: <20100615162505.GB31149@libertas.local.camdensoftware.com> References: <4C173909.1050101@comclark.com> <4C174283.9090903@comclark.com> <20100615162505.GB31149@libertas.local.camdensoftware.com>
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Chip Camden wrote:
> On Jun 15 2010 17:06, Aiza wrote:
>> Aiza wrote:
>>> I have a directory with files in it. The first 3 letters of the file
>>> names is the group prefix. I'm trying to write a script to accept the 3
>>> letter of the group followed by a * to mean its a prefix lookup. But
>>> when I run it I get a message "NO match" that is not issued by the
>>> script. Its like * is not allowed as input.
>>>
>>> Looking for sample .sh code for handling this standard type of lookup or
>>> some online tutorial that has sample code for bourne shell programming.
>>>
>>
>>
>> Here is the code
>>
>> prefix_name1=$1
>> prefix_name2=`echo -n "${prefix_name1}" | sed 's/*.*$//'`
>> echo "prefix_name1 = ${prefix_name1}"
>> echo "prefix_name2 = ${prefix_name2}"
>>
>>
>> if [ ${prefix_name1} -nq ${prefix_name2} ]; then
>> echo "prefix_name2 = ${prefix_name2}"
>> fi
>> exerr "hard stop"
>>
>>
>> Here is the test and out put
>> # >admin cell*
>> admin: No match.
>>
>
> As others have mentioned, you need to quote or escape the * in the
> command line:
>
> admin "cell*"
>
> You've also botched your regex (/*.*$/) -- it can't begin with a *. What exactly
> are you trying to match?
>
As shown in the posted test results you can see that the * is removed
from the input cell* and becomes cell and then cell* is compared to cell
to determine if a search by prefix command was entered on the script
command line. So the regex (/*.*$/) is working as coded as long as the
script command line is coded like this "cell*".
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