Date: Fri, 11 Jun 1999 13:08:31 -0400 (EDT) From: Mikhail Teterin <mi@misha.cisco.com> To: FreeBSD-gnats-submit@freebsd.org Subject: bin/12137: something wrong with shell -- functions with arithm expressions Message-ID: <199906111708.NAA57393@misha.cisco.com>
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>Number: 12137
>Category: bin
>Synopsis: something wrong with shell -- functions with arithm expressions
>Confidential: no
>Severity: serious
>Priority: medium
>Responsible: freebsd-bugs
>State: open
>Quarter:
>Keywords:
>Date-Required:
>Class: sw-bug
>Submitter-Id: current-users
>Arrival-Date: Fri Jun 11 10:10:01 PDT 1999
>Closed-Date:
>Last-Modified:
>Originator: Mikhail Teterin
>Release: FreeBSD 3.2-STABLE i386
>Organization:
Virtual Estates, Inc.
>Environment:
>Description:
This strange method of figuring out the length of a string gives
different results for the strings of the same length depending on
their content:
length () {
echo $((0 + ${#1}))
}
length "abc (def [xyz])"
length "abc (def (xyz))"
The use of ``[]'' makes the string appear one character longer. I
made the severity and priority fairly high, because this may
indicate some brokenness in more important parts of sh.
A more simple attempt to reproduce this:
a="abc (def [xyz])"
echo $((0+${#a}))
b="abc (def (xyz))"
echo $((0+${#b}))
works as expected -- same length for both strings. So does:
length () {
echo ${#1}
}
length "abc (def [xyz])"
length "abc (def (xyz))"
You actually need the combination of arithmetic and function, it seems.
>How-To-Repeat:
Just run the script above with sh. I see:
16
15
>Fix:
Use bash or ksh -- they both produce 15 for both of this lines.
>Release-Note:
>Audit-Trail:
>Unformatted:
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