Date: Wed, 18 Jul 2001 15:53:09 -0700 From: Etienne de Bruin <et@quidel.com> To: 'John Baldwin' <jhb@FreeBSD.org>, Etienne de Bruin <et@quidel.com> Cc: "freebsd-hackers@freebsd.org" <freebsd-hackers@FreeBSD.org> Subject: RE: release.8 (4.3-RELEASE) Message-ID: <9D4A4E19244ED4119BE90050DAD5DD47BC554A@mail.quidel.com>
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But what does this accomplish in the contect of release.8 if our purpose is to 'copy' all the binaries to the new mfsroot? On 18-Jul-01 Etienne de Bruin wrote: > I was reading the Makefile in /usr/src/release and wondering about the > > for dir in bin sbin ; do \ > ln -sf /stand $$dir; \ > done > > part in release.8 - it is my understanding that all that is under /stand is > linked to files in $$dir. > > What does this accomplish? No, it links $$dir to /stand. This creates /sbin and /bin directories so that you can still see /bin/ls even though ls is really in /stand/ls. This is to make a "normal" path work right, and to allow scripts which assume the default location of utilities work. -- John Baldwin <jhb@FreeBSD.org> -- http://www.FreeBSD.org/~jhb/ PGP Key: http://www.baldwin.cx/~john/pgpkey.asc "Power Users Use the Power to Serve!" - http://www.FreeBSD.org/ To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-hackers" in the body of the message
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