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Date: Mon, 11 Aug 2003 18:35:17 -0400
From: Constantine <cnst@rbcmail.ru>
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To: Michael Conlen <meconlen@obfuscated.net>
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cc: freebsd-questions@freebsd.org
Subject: Re: simple sh scripting. How to put a result of a command to a
	variable?
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Michael Conlen wrote:

> Constantine wrote:
>
>> I am writing a script, which involves unzipping some files. I would 
>> have to unzip 4 different zip-files from some directory, and I would 
>> need to unzip them to the directory, which would have the same name 
>> in it as the original zip-file, i.e. I would like to run something 
>> like "ls *.zip", have each file name recorded in some variable, and 
>> do a loop like "unzip $filename[$i] -d $filename[$i].unzipped/". Can 
>> someone help me with the code? How can I put the results of a command 
>> to a variable? 
>
> If I understand you properly I think the following would do what you want
>
> #!/bin/sh
> for i in `ls *.zip`
> do
>    unzip ${i} -d ${i}.unzipped
> done 

Thank you very much indeed! Seems just what I wanted. But can I save the 
archive names in an array for further manipulation? Also, how can I type 
that apostrophe ` from my keyboard?

Cheers,
Constantine.