Date: Tue, 28 Dec 1999 11:56:03 -0800 (PST) From: Joss Roots <osiris2002@yahoo.com> To: freebsd-questions@freebsd.org Subject: Is there a way to do this using ls command ? Message-ID: <19991228195603.2204.qmail@web115.yahoomail.com>
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hi there, I am trying to make a shell script get the names of directories from a certain path; /usr/ports/audio and I want to just put the output into a file say /home/joss/ports-audio that's the easy part. The thing I want for this script is to do some inteliigent step(s) to do the following: 1. don't include, or otherwise strip, all entries that are NOT directories, so as NOT to save them in the generated output file for example ls -F | grep / (but this will output a trailing / after each and every directory name), so how to strip this can this be done using sed, or something else ? 2. Remove certain directory entries form the list, for example CVS/ , pkg/ before saving the final output to the file. 3. the list must be sequential listing one entry on a seperate line. (like issuing simple ls) can anyone help me through this. thanks in advance. ===== MAY THE FORCE BE WITH YOU. __________________________________________________ Do You Yahoo!? Talk to your friends online with Yahoo! Messenger. http://messenger.yahoo.com To Unsubscribe: send mail to majordomo@FreeBSD.org with "unsubscribe freebsd-questions" in the body of the message
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