Date: Thu, 19 Jul 2007 23:23:45 -0400 From: "Michael B Allen" <ioplex@gmail.com> To: freebsd-hackers <freebsd-hackers@freebsd.org> Subject: Re: Path to executable of current process? Message-ID: <78c6bd860707192023u645a3c39ua713cc4384c3b876@mail.gmail.com> In-Reply-To: <78c6bd860707191900g375f98ado8315603feac50247@mail.gmail.com> References: <78c6bd860707191725r14b8bfe3sf15c1f0e30cf82ca@mail.gmail.com> <78c6bd860707191900g375f98ado8315603feac50247@mail.gmail.com>
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> Is there any way to get argv[0] for [a particular] process without being root?
After more digging I see sysctl seems to be the way to do this but can I get
the full path to the executable form kinfo_proc?
How does ps do this?
static const char *
getcmdline(pid_t pid)
{
static struct kinfo_proc ki_proc;
int mib[4], len;
mib[0] = CTL_KERN;
mib[1] = KERN_PROC;
mib[2] = KERN_PROC_PID;
mib[3] = pid;
len = sizeof(struct kinfo_proc);
if (sysctl(mib, 4, &ki_proc, &len, NULL, 0) == -1)
return NULL;
return ki_proc.ki_???
}
Mike
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