Date: Mon, 04 Apr 2022 23:08:44 +0900 From: Byung-Hee HWANG <soyeomul@doraji.xyz> To: questions@freebsd.org Subject: Re: extracting an IPv4 address from text? Message-ID: <87ee2daqkz.fsf@penguin> In-Reply-To: <25160.44484.392802.868667@jerusalem.litteratus.org> (Robert Huff's message of "Sat, 2 Apr 2022 16:10:44 -0400") References: <25160.44484.392802.868667@jerusalem.litteratus.org>
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Dear Robert,
Robert Huff <roberthuff@rcn.com> writes:
> Hello:
> Let's suppose I want to parse a line from auth.log and extract
> the IP address (if any) to stdout.
> (...thanks...)
#+BEGIN_SRC python
# -*- coding: utf-8 -*
import re
p =3D re.compile("\
[1-9]?[0-9]?[0-9]\.[0-9]?[0-9]?[0-9]\.[0-9]?[0-9]?[0-9]\.[0-9]?[0-9]?[0-9]")
FPATH =3D "auth.log" # you can edit here
f =3D open(FPATH, "r")
data =3D f.read()
f.close()
result =3D p.findall(data) # <class 'list'>
if __name__ =3D=3D "__main__":
print(result)
print(len(result))
#+END_SRC
It is python3 script, thanks!
Sincerely, Byung-Hee
--=20
^=EA=B3=A0=EB=A7=99=EC=8A=B5=EB=8B=88=EB=8B=A4 _=E7=99=BD=E8=A1=A3=E5=BE=9E=
=E8=BB=8D_ =EA=B0=90=EC=82=AC=ED=95=A9=EB=8B=88=EB=8B=A4_^))//
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