Date: Tue, 28 Dec 1999 22:06:44 +0100 (CET) From: Oliver Fromme <olli@dorifer.heim3.tu-clausthal.de> To: freebsd-questions@FreeBSD.ORG Subject: Re: Is there a way to do this using ls command ? Message-ID: <199912282106.WAA28363@dorifer.heim3.tu-clausthal.de>
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Joss Roots wrote in list.freebsd-questions:
> hi there,
> I am trying to make a shell script get the names
> of directories from a certain path;
> [...]
> 1. don't include, or otherwise strip, all entries
> that are NOT directories, so as NOT to save them
> in the generated output file
> for example ls -F | grep /
> (but this will output a trailing / after each and
> every directory name), so how to strip this
> can this be done using sed, or something else ?
ls -F | sed -n s./..p
That will give you all directories and strip the slashes at the
same time.
> 2. Remove certain directory entries form the
> list, for example CVS/ , pkg/
> before saving the final output to the file.
Just pipe the above through an appropriate grep command:
... | egrep '^(CVS|pkg)$'
> 3. the list must be sequential listing one entry
> on a seperate line. (like issuing simple ls)
The above does exactly that. Use shell direction to store the
output in a file:
... > output_file
Regards
Oliver
--
Oliver Fromme, Leibnizstr. 18/61, 38678 Clausthal, Germany
(Info: finger userinfo:olli@dorifer.heim3.tu-clausthal.de)
"In jedem Stück Kohle wartet ein Diamant auf seine Geburt"
(Terry Pratchett)
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