From owner-freebsd-net@FreeBSD.ORG Tue May 20 23:37:51 2003 Return-Path: Delivered-To: freebsd-net@freebsd.org Received: from mx1.FreeBSD.org (mx1.freebsd.org [216.136.204.125]) by hub.freebsd.org (Postfix) with ESMTP id C6C6637B408 for ; Tue, 20 May 2003 23:37:51 -0700 (PDT) Received: from mailer.cat.co.za (pop.cat.co.za [196.33.33.51]) by mx1.FreeBSD.org (Postfix) with SMTP id 7A50843FAF for ; Tue, 20 May 2003 23:37:45 -0700 (PDT) (envelope-from bradd@cat.co.za) Received: (qmail 4868 invoked from network); 21 May 2003 06:36:50 -0000 Received: from unknown (HELO 161?DEMO?400) (196.33.33.52) by mail.cat.co.za with SMTP; 21 May 2003 06:36:50 -0000 Content-Type: text/plain; charset="us-ascii" From: Brad du Plessis To: net@freebsd.org Date: Wed, 21 May 2003 08:32:23 +0200 User-Agent: KMail/1.4.3 MIME-Version: 1.0 Content-Transfer-Encoding: quoted-printable Message-Id: <200305210832.23046.bradd@cat.co.za> Subject: Packet mode in UserPPP X-BeenThere: freebsd-net@freebsd.org X-Mailman-Version: 2.1.1 Precedence: list List-Id: Networking and TCP/IP with FreeBSD List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-List-Received-Date: Wed, 21 May 2003 06:37:53 -0000 Hi Not sure if this should rather have gone to ISDN but I'll try here anyway= =2E.. Could anyone tell me exactly what packet mode does in UserPPP and if stan= dard=20 PPP has an equivalent mode for negotiating a connection. It appears to me= =20 that ML-PPP is the only standard 128KB protocol between ISDN TAs and I ca= n=20 only get my two TA's to connect with this protocol in UserPPP by entering= =20 packet mode. Is there a way to do it with standard PPP?? Thanks Brad