Date: Wed, 19 Sep 2001 05:52:01 +0200 From: Gunnar Flygt <flygt@sr.se> To: j mckitrick <jcm@freebsd-uk.eu.org> Cc: FreeBSD Stable <freebsd-stable@freebsd.org> Subject: Re: Why does installing X require the compat3x and compat4x dists Message-ID: <20010919055201.A51892@sr.se> In-Reply-To: <20010918173514.B51703@dogma.freebsd-uk.eu.org>; from jcm@FreeBSD-uk.eu.org on Tue, Sep 18, 2001 at 05:35:14PM %2B0100 References: <20010918012828.A98117@dragon.nuxi.com> <008301c1405d$0aa33990$38934dc7@cnd.gatech.edu> <20010918173514.B51703@dogma.freebsd-uk.eu.org>
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On Tue, Sep 18, 2001 at 05:35:14PM +0100, j mckitrick wrote:
> On Tue, Sep 18, 2001 at 12:14:49PM -0400, Jeff Lee wrote:
> | -----BEGIN PGP SIGNED MESSAGE-----
> | Hash: SHA1
> |
> | I've never understood that either, but I assumed that someone had a
> | good reason for it. Why is XFree86 3.3.6 installed by default
> | instead of 4.X?
>
> I *believe* for two reasons:
>
> When 4.x came out, it was considered less secure.
> 4.x didn't support as many chipsets as 3.x, so for maximum useability, they
> just go with 3.x.
>
> I've tried getting 4.x to work on my machine and it doesn't. I'll try again
> when I can install from CD, or at least install the latest port, which might
> work better.
I've ran 4.x since 4.0.1 came out. On 7 different boxes including one
laptop. No problems, except for the config utility xf86cfg that have
worked on only one of the machines.
--
__o
regards, Gunnar ---_ \<,_
email: flygt@sr.se ---- (_)/ (_)
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