Date: Tue, 31 Aug 1999 05:47:49 +0100 From: Brian Somers <brian@Awfulhak.org> To: Greg Lehey <grog@lemis.com> Cc: Brian Somers <brian@Awfulhak.org>, Roelof Osinga <roelof@nisser.com>, Patrick Seal <patseal@hyperhost.net>, freebsd-questions@FreeBSD.ORG Subject: Re: Bash: space in cd arg bug? Message-ID: <199908310447.FAA27918@keep.lan.Awfulhak.org> In-Reply-To: Your message of "Tue, 31 Aug 1999 11:52:27 %2B0930." <19990831115226.X13904@freebie.lemis.com>
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> On Tuesday, 31 August 1999 at 0:02:20 +0100, Brian Somers wrote:
> > [.....]
> >>> You missed the
> >>>
> >>> zsh -> echo $FOO
> >>> /C:/Program Files
> >>> zsh -> mkdir $FOO
> >>>
> >>> Which makes two directories. Why should ``cd'' behave differently
> >>> from an external command - just because it's a builtin ?
> >>
> >> It shouldn't.
> >>
> >>> IMHO, zsh is wrong.
> >>
> >> Agreed. And bash does exactly the same thing in this case.
> >
> > Someone said that ``cd $FOO'' was being interpreted as
> > ``cd "Program Files"'' (two words) rather than as
> > ``cd Program Files'' (three words). The correct interpretation
> > (which is the same as bash's interpretation) is as three words.
>
> Why is this correct? How do I store a directory name which contains
> in a variable and then change to it? It's not correct just to cd $*
> instead of cd $1, because there could be multiple contiguous spaces in
> the directory name.
No, it's correct to ``cd "$FOO"'' if you want to allow characters in
$IFS to be embedded in $FOO.
> Greg
> --
> See complete headers for address, home page and phone numbers
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>
--
Brian <brian@Awfulhak.org> <brian@FreeBSD.org>
<http://www.Awfulhak.org>; <brian@OpenBSD.org>
Don't _EVER_ lose your sense of humour ! <brian@FreeBSD.org.uk>
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