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Date: Mon, 5 Mar 2007 16:35:06 -0800
From: Gary Kline <kline@tao.thought.org>
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Subject: awk question
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	Guys,

	Having found $9 , how do I /bin/rm it (using system()--yes??)
	in an awk one-liner?

	I'm trying to remove from packages from long ago and find and
	print them with

	ls -lt | awk '{if ($8 == 2006) print $9}';

	but what I want to remove the file pointed at by $9.  I've tried
	FILE=ARGV[9]; and using FILE within my system() call, but no-joy.
	What's the magic here?

	thanks in advance,

	gary



-- 
  Gary Kline  kline@thought.org   www.thought.org  Public Service Unix