Date: Mon, 5 Mar 2007 16:42:34 -0800 From: Bill Campbell <freebsd@celestial.com> To: freebsd-questions@freebsd.org Subject: Re: awk question Message-ID: <20070306004234.GA15353@ayn.mi.celestial.com> In-Reply-To: <20070306003506.GA12553@thought.org> References: <20070306003506.GA12553@thought.org>
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On Mon, Mar 05, 2007, Gary Kline wrote:
>
> Guys,
>
> Having found $9 , how do I /bin/rm it (using system()--yes??)
> in an awk one-liner?
>
> I'm trying to remove from packages from long ago and find and
> print them with
>
> ls -lt | awk '{if ($8 == 2006) print $9}';
>
> but what I want to remove the file pointed at by $9. I've tried
> FILE=ARGV[9]; and using FILE within my system() call, but no-joy.
> What's the magic here?
A better way to do this might be to use find and xargs. The
command below would remove all files under the current directory
that haven't been modified in the 360 days.
find . -type f -mtime +360 -print0 | xargs -0 rm
If you don't want it to go into subdirectories:
find . -maxdepth 1 -type f -mtime +360 -print0 | xargs -0 rm
Bill
--
INTERNET: bill@Celestial.COM Bill Campbell; Celestial Software LLC
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