Date: Thu, 14 Nov 2002 14:33:54 +0100 From: Boris Nikolaus <boris@cs.tu-berlin.de> To: FreeBSD-gnats-submit@FreeBSD.org Subject: kern/45291: kevent(2) ignores timeout if nevents == 0 Message-ID: <20021114133354.GA13558@fiesta.cs.tu-berlin.de>
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>Number: 45291
>Category: kern
>Synopsis: kevent(2) ignores timeout if nevents == 0
>Confidential: no
>Severity: non-critical
>Priority: low
>Responsible: freebsd-bugs
>State: open
>Quarter:
>Keywords:
>Date-Required:
>Class: sw-bug
>Submitter-Id: current-users
>Arrival-Date: Thu Nov 14 05:40:01 PST 2002
>Closed-Date:
>Last-Modified:
>Originator: Boris Nikolaus
>Release: FreeBSD 4.7-STABLE i386
>Organization:
>Environment:
System: FreeBSD XXXXX 4.7-STABLE FreeBSD 4.7-STABLE #43: Tue Oct 22 20:25:44 CEST 2002 root@XXXXXX:/usr/src/sys/compile/BORIS i386
>Description:
kevent(2) returns immediatly (ignoring the given timeout) if the "nevents"
parameter is 0. I would expect that it sleeps the time (similar to
poll(2)/select(2)).
>How-To-Repeat:
This program terminates immediately instead of sleeping for 10 seconds:
#include <stdio.h>
#include <sys/types.h>
#include <sys/event.h>
#include <sys/time.h>
int main() {
int qfd;
struct timespec ts;
int ret;
qfd = kqueue();
ts.tv_sec = 10;
ts.tv_nsec = 0;
ret = kevent(qfd, NULL, 0, NULL, 0, &ts);
printf("kevent returned %d\n", ret);
return 0;
}
>Fix:
Problem can be circumvented by calling "nanosleep(&ts, NULL)" if the nevents
parameter would be 0.
>Release-Note:
>Audit-Trail:
>Unformatted:
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