Date: Fri, 4 Mar 2016 09:56:01 -0500 From: David Banning <david+dated+1457535364.ac3c82@skytracker.ca> To: Polytropon <freebsd@edvax.de> Cc: questions@freebsd.org Subject: Re: sed help please Message-ID: <20160304145601.GA24579@skytracker.ca> In-Reply-To: <20160304053557.ff32d984.freebsd@edvax.de> References: <20160304040536.GA7729@skytracker.ca> <20160304053557.ff32d984.freebsd@edvax.de>
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On Fri, Mar 04, 2016 at 05:35:57AM +0100, Polytropon wrote: > On Thu, 3 Mar 2016 23:05:36 -0500, David Banning wrote: > > I am trying to change hundreds of lines of text. Given the following text; > > > > line 1 > > line 2 foo take this text > > line 3 > > line 4 > > line 5 bar leave this text > > line 6 > > line 7 > > > > I need a sed command that would take everything between foo and bar - > > including foo and bar. > > > > Ideally the output would look like; > > > > line 1 > > line 2 > > leave this text > > line 6 > > line 7 > > > > Keep in mind that foo and bar appear in different > > locations - sometimes at the beginning of a line, sometimes at the end, > > and sometimes in the middle. > > Does it have to be sed? When I read your requirement, I immediately > thought about the EXAMPLES section in "man awk", where you'll find: > > /start/, /stop/ > Print all lines between start/stop pairs. > > You could try this first: > > awk -f '/foo/, /bar/' < input.txt > output.txt > > Not verified, though. It can't work with lines. Because I need keep the text before foo and after bar, and that text may or may not be on the same line with text that needs to be saved or cut.
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