Date: Tue, 8 Jan 2002 16:01:36 -0800 From: Kris Kennaway <kris@obsecurity.org> To: aaron <aaron@lo-res.org> Cc: dooleyr@missouri.edu, freebsd-stable@FreeBSD.ORG Subject: Re: This is probably a FAQ question... Message-ID: <20020108160136.A75254@xor.obsecurity.org> In-Reply-To: <200201082329.g08NT9v70337@meta.lo-res.org>; from aaron@lo-res.org on Wed, Jan 09, 2002 at 12:29:07AM %2B0100 References: <Pine.LNX.4.33.0201081708580.28507-100000@radon.bengal.missouri.edu> <200201082329.g08NT9v70337@meta.lo-res.org>
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[-- Attachment #1 --] On Wed, Jan 09, 2002 at 12:29:07AM +0100, aaron wrote: > Hm, ok the FAQ, but.... > recently - as seen on the well known mailing lists - there was a post > that 48bit addressing is now available. If I understood it correctly this > should give you (at least!) 2^48 = 256 TBytes. > > But I myself would like to know if this calculation is correct. > (or is it 2^48 blocks?) Device size != Partition size != Filesystem size != File size 48-bit addressing is for addressing raw disk blocks on the device. Kris [-- Attachment #2 --] -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.0.6 (FreeBSD) Comment: For info see http://www.gnupg.org iD8DBQE8O4hfWry0BWjoQKURAggaAKD4qK0b8obj7ytjshLkxQES5xSI+ACfeuKh akLqMLQvtDNeAOiIbBguDgg= =H4rJ -----END PGP SIGNATURE-----
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