Date: Sun, 10 Feb 2008 12:23:54 +0200 From: =?utf-8?B?Q2loYW4gS8O2bWXDp2/En2x1?= <cihan@enderunix.org> To: freebsd-hackers@freebsd.org Subject: abort? Message-ID: <1623050662.20080210122354@enderunix.org>
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Hello list I cant understand why kill function is called two times to send sigabort signal. One signal to send is enough, isn't it? Thanks void abort(void) /* POSIX-style abort() function */ { sigset_t mask; struct sigaction action; /* * Caller can't ignore SIGABRT, if so reset to default. */ sigaction(SIGABRT, NULL, &action); if (action.sa_handler =3D=3D SIG_IGN) { action.sa_handler =3D SIG_DFL; sigaction(SIGABRT, &action, NULL); } if (action.sa_handler =3D=3D SIG_DFL) fflush(NULL); /* flush all open stdio streams */ /* * Caller can't block SIGABRT; make sure it's unblocked. */ sigfillset(&mask); sigdelset(&mask, SIGABRT); /* mask has only SIGABRT turned off */ sigprocmask(SIG_SETMASK, &mask, NULL); kill(getpid(), SIGABRT); /* send the signal */ /* * If we're here, process caught SIGABRT and returned. */ fflush(NULL); /* flush all open stdio streams */ action.sa_handler =3D SIG_DFL; sigaction(SIGABRT, &action, NULL); /* reset to default */ sigprocmask(SIG_SETMASK, &mask, NULL); /* just in case ... */ kill(getpid(), SIGABRT); /* and one more time */ exit(1); /* this should never be executed ... */ } =20 --=20 Cihan K=F6me=E7o=F0lu, EnderUNIX SDT mailto:cihan@enderunix.org
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