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Date:      Sun, 10 Feb 2008 12:23:54 +0200
From:      =?utf-8?B?Q2loYW4gS8O2bWXDp2/En2x1?= <cihan@enderunix.org>
To:        freebsd-hackers@freebsd.org
Subject:   abort?
Message-ID:  <1623050662.20080210122354@enderunix.org>

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Hello list

I cant understand why kill function is called two times to send
sigabort signal. One signal to send is enough, isn't it?

Thanks



void
abort(void)         /* POSIX-style abort() function */
{
    sigset_t           mask;
    struct sigaction   action;

    /*
     * Caller can't ignore SIGABRT, if so reset to default.
     */
    sigaction(SIGABRT, NULL, &action);
    if (action.sa_handler =3D=3D SIG_IGN) {
        action.sa_handler =3D SIG_DFL;
        sigaction(SIGABRT, &action, NULL);
    }
    if (action.sa_handler =3D=3D SIG_DFL)
        fflush(NULL);           /* flush all open stdio streams */

    /*
     * Caller can't block SIGABRT; make sure it's unblocked.
     */
    sigfillset(&mask);
    sigdelset(&mask, SIGABRT);  /* mask has only SIGABRT turned off */
    sigprocmask(SIG_SETMASK, &mask, NULL);
    kill(getpid(), SIGABRT);    /* send the signal */

    /*
     * If we're here, process caught SIGABRT and returned.
     */
    fflush(NULL);               /* flush all open stdio streams */
    action.sa_handler =3D SIG_DFL;
    sigaction(SIGABRT, &action, NULL);  /* reset to default */
    sigprocmask(SIG_SETMASK, &mask, NULL);  /* just in case ... */
    kill(getpid(), SIGABRT);                /* and one more time */
    exit(1);    /* this should never be executed ... */
}
=20

--=20
Cihan K=F6me=E7o=F0lu,
EnderUNIX SDT                         mailto:cihan@enderunix.org




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