Date: Mon, 19 Aug 2002 12:09:42 -0400 From: "C. A. Daelhousen" <cd9@buffalo.edu> To: Mikhail Teterin <mi+mx@aldan.algebra.com> Cc: freebsd-questions@freebsd.org Subject: Re: pow(3) on FreeBSD Message-ID: <20020819120942.A65360@selvirjin.alltel.net> In-Reply-To: <200208191124.35129.mi%2Bmx@aldan.algebra.com>; from mi%2Bmx@aldan.algebra.com on Mon, Aug 19, 2002 at 11:24:35AM -0400 References: <200208190413.g7J4DEcw051123@corbulon.video-collage.com> <20020819043012.GN74231@dan.emsphone.com> <200208191124.35129.mi%2Bmx@aldan.algebra.com>
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On Mon, Aug 19, 2002 at 11:24:35AM -0400, Mikhail Teterin wrote:
> There is nothing complex (pun intended) about, say, 1^2.5. It is still
> 1. -- unless you are running FreeBSD (Linux?)... There is nothing
> complex about Dan's's example (2^1.5) above either -- the correct value
> is 2.828427, but it is 0 on FreeBSD -- in accordance with the man-page
> and in disagreement with Dan...
>
> Now, can someone, please, offer the REAL reasons for the FreeBSD's
> apparent defficiency? May be, even a double-precision workaround --
> unlike powf(3), which operates on float-precision numbers?..
>
It works for me.
c/pow.c:
#include <math.h>
#include <stdio.h>
int main() { printf("%e\n", pow(2,1.5)); return 0; }
compile/run:
$ gcc30 -O2 -march=athlon -pipe -o bin/pow -lm -Wall c/pow.c
$ bin/pow
2.828427e+00
$ uname -a
FreeBSD <host> 4.6.2-RELEASE FreeBSD 4.6.2-RELEASE #0:
Sun Aug 18 19:22:25 EDT 2002
root@<host>:/usr/obj/usr/src/sys/V8 i386
--
..: Chad Daelhousen == cd9@buffalo.edu :.........: sig v3.1 :...
: Programming for 10 +/- 2 years (50 +/- 10% of a lifetime) :
:.............Perl will be the first to implement mind reading.:
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