Date: Mon, 31 Aug 2009 01:36:41 +0200 From: Erik Trulsson <ertr1013@student.uu.se> To: Stefan Miklosovic <miklosovic.freebsd@gmail.com> Cc: freebsd-questions@freebsd.org Subject: Re: shell command line argument + parsing function Message-ID: <20090830233641.GA48910@owl.midgard.homeip.net> In-Reply-To: <f99a79ec0908301607l7772a486j1986b87d31d33cef@mail.gmail.com> References: <f99a79ec0908301607l7772a486j1986b87d31d33cef@mail.gmail.com>
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On Mon, Aug 31, 2009 at 01:07:36AM +0200, Stefan Miklosovic wrote:
> hi,
>
> assuming I execute shell script like this
>
> $ ./script -c "hello world"
>
> I want to save "hello world" string to variable COMMENT in shell script.
>
> code:
>
> #!/bin/sh
>
> parse_cmdline() {
> while [ $# -gt 0 ]; do
> case "$1" in
> -c)
> shift
> COMMENT="$1"
> ;;
> esac
> shift
> done
> }
>
> parse_cmdline $*
>
> echo $COMMENT
>
> exit 0
>
> but that only write out "hello". I tried to change $* to $@, nothing
> changed.
But if you use "$@" (with the quote marks) instead it should work fine.
For further explanation please read the sh(1) man page where it explains the
special parameters $* and $@, while paying special attention to how they
expand when used within double-quotes.
>
> It is interesting, that if I dont put "while" loop into function
> parse_cmdline,
> and do echo $COMMENT, it writes "hello world".
>
> I WANT that function style. How to do it ?
>
> thank you
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--
<Insert your favourite quote here.>
Erik Trulsson
ertr1013@student.uu.se
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